1) Cho a,b,c>0 tm a+b+c=3. Cmr \(\frac{1}{2+a^2+b^2}+\frac{1}{2+b^2+c^2}+\frac{1}{2+c^2+a^2}\le\frac{3}{4}\)

2) Cho a,b,c>0 tm a^2+b^2+c^2 bé hơn hoặc bằng abc. Cmr \(\frac{a}{a^2+bc}+\frac{b}{b^2+ca}+\frac{c}{c^2+ab}\le\frac{1}{2}\)

3) Cho a,b,c>0 tm a+b+c<=3. Cmr \(\frac{ab}{\sqrt{3+c}}+\frac{bc}{\sqrt{3+a}}+\frac{ca}{\sqrt{3+b}}\le\frac{3}{2}\)

4) Cho a,b,c>0 tm a+b+c=2. Cmr \(\frac{a}{\sqrt{4a+3bc}}+\frac{b}{\sqrt{4b+3ca}}+\frac{c}{\sqrt{4c+3ab}}\le1\)

5) Cho a,b,c>0. Cmr \(\sqrt{\frac{a^3}{5a^2+\left(b+c\right)^2}}+\sqrt{\frac{b^3}{5b^2+\left(c+a\right)^2}}+\sqrt{\frac{c^3}{5c^2+\left(a+b\right)^2}}\le\sqrt{\frac{a+b+c}{3}}\)

6) Cho a,b,c>0. Cmr \(\frac{a^2}{\left(2a+b\right)\left(2a+c\right)}+\frac{b^2}{\left(2b+a\right)\left(2b+c\right)}+\frac{c^2}{\left(2c+a\right)\left(2c+b\right)}\le\frac{1}{3}\)

Giúp mình với nhé các bạn

1. a) \(\left\{{}\begin{matrix}x,y,z>0\\xyz=1\end{matrix}\right.\). Tìm max \(P=\frac{1}{\sqrt{x^5-x^2+3xy+6}}+\frac{1}{\sqrt{y^5-y^2+3yz+6}}+\frac{1}{\sqrt{z^5-z^2+zx+6}}\)

b) \(\left\{{}\begin{matrix}x,y,z>0\\xyz=8\end{matrix}\right.\). Min \(P=\frac{x^2}{\sqrt{\left(1+x^3\right)\left(1+y^3\right)}}+\frac{y^2}{\sqrt{\left(1+y^3\right)\left(1+z^3\right)}}+\frac{z^2}{\sqrt{\left(1+z^3\right)\left(1+x^3\right)}}\)

c) \(x,y,z>0.\) Min \(P=\sqrt{\frac{x^3}{x^3+\left(y+z\right)^3}}+\sqrt{\frac{y^3}{y^3+\left(z+x\right)^3}}+\sqrt{\frac{z^3}{z^3+\left(x+y\right)^3}}\)

d) \(a,b,c>0;a^2+b^2+c^2+abc=4.Cmr:2a+b+c\le\frac{9}{2}\)

e) \(\left\{{}\begin{matrix}a,b,c>0\\a+b+c=3\end{matrix}\right.\). Cmr: \(\frac{a}{b^3+ab}+\frac{b}{c^3+bc}+\frac{c}{a^3+ca}\ge\frac{3}{2}\)

f) \(\left\{{}\begin{matrix}a,b,c>0\\ab+bc+ca+abc=4\end{matrix}\right.\) Cmr: \(\sqrt{ab}+\sqrt{bc}+\sqrt{ca}\le3\)

g) \(\left\{{}\begin{matrix}a,b,c>0\\ab+bc+ca+abc=2\end{matrix}\right.\) Max : \(Q=\frac{a+1}{a^2+2a+2}+\frac{b+1}{b^2+2b+2}+\frac{c+1}{c^2+2c+2}\)

1) Cho x > 1. Tìm GTNN của:   ​\(A=\frac{1+x^4}{x\left(x-1\right)\left(x+1\right)}\)

2) Trong các cặp (x;y) thỏa mãn \(\frac{x^2-x+y^2-y}{x^2+y^2-1}\le0\). Tìm cặp có tổng x + 2y lớn nhất.

3) Cho x thỏa mãn \(x^2+\left(3-x\right)^2\ge5\). Tìm GTNN của \(A=x^4+\left(3-x\right)^4+6x^2\left(3-x\right)^2\)

4) Tìm GTNN của \(Q=\frac{1}{2}\left(\frac{x^{10}}{y^2}+\frac{y^{10}}{x^2}\right)+\frac{1}{4}\left(x^{16}+y^{16}\right)-\left(1+x^2y^2\right)^2\)

5) Cho x, y > 1. Tìm GTNN của \(P=\frac{\left(x^3+y^3\right)-\left(x^2+y^2\right)}{\left(x-1\right)\left(y-1\right)}\)

6) Cho x, y, z > 0 thỏa mãn: \(xy^2z^2+x^2z+y=3z^2\). Tìm GTLN của \(P=\frac{z^4}{1+z^4\left(x^4+y^4\right)}\)

7) Cho a, b, c > 0. CMR:\(\frac{a^2}{b^2+c^2}+\frac{b^2}{a^2+c^2}+\frac{c^2}{a^2+b^2}\ge\frac{a}{b+c}+\frac{b}{a+c}+\frac{c}{a+b}\)

8) Cho x>y>0. và \(x^5+y^5=x-y\). CMR: \(x^4+y^4<1\)

9) Cho \(1\le a,b,c\le2\). CMR: \(\left(a+b+c\right)\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\le10\)

10) Cho \(x,y,z\ge0\)CMR: \(\sqrt[3]{x}+\sqrt[3]{y}+\sqrt[3]{z}\le\sqrt[3]{\frac{x+y}{2}}+\sqrt[3]{\frac{y+z}{2}}+\sqrt[3]{\frac{z+x}{2}}\)

11) Cho \(x,y\ge0\)thỏa mãn \(x^2+y^2=1\)CMR: \(\frac{1}{\sqrt{2}}\le x^3+y^3\le1\)

12) Cho a,b,c > 0 và a + b + c = 12. CM: \(\sqrt{3a+2\sqrt{a}+1}+\sqrt{3b+2\sqrt{b}+1}+\sqrt{3c+2\sqrt{c}+1}\le3\sqrt{17}\)

13) Cho x,y,z < 0 thỏa mãn \(x+y+z\le\frac{3}{2}\). CMR: \(\sqrt{x^2+\frac{1}{x^2}}+\sqrt{y^2+\frac{1}{y^2}}+\sqrt{z^2+\frac{1}{z^2}}\ge3\sqrt{17}\)

14) Cho a,b > 0. CMR: \(\left(\sqrt[6]{a}+\sqrt[6]{b}\right)\left(\sqrt[3]{a}+\sqrt[3]{b}\right)\left(\sqrt{a}+\sqrt{b}\right)\le4\left(a+b\right)\)

15) Với a, b, c > 0. CMR: \(\frac{a^8+b^8+c^8}{a^3.b^3.c^3}\ge\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\)

16) Cho x, y, z > 0 và \(x^3+y^3+z^3=1\)CMR: \(\frac{x^2}{\sqrt{1-x^2}}+\frac{y^2}{\sqrt{1-y^2}}+\frac{z^2}{\sqrt{1-z^2}}\ge2\)

1. \(\left\{{}\begin{matrix}a,b,c>0\\a+b+c=1\end{matrix}\right.\). Cmr: \(\frac{ab}{\sqrt{\left(1-c\right)^2\left(1+c\right)}}+\frac{bc}{\sqrt{\left(1-a\right)^2\left(1+a\right)}}+\frac{ca}{\sqrt{\left(1-b\right)^3\left(1+b\right)}}\le\frac{3\sqrt{2}}{8}\)

2. \(\left\{{}\begin{matrix}a,b,c>0\\a+b+c\le1\end{matrix}\right.\). Cmr: \(\frac{1}{a^2+b^2+c^2}+\frac{1}{ab\left(a+b\right)}+\frac{1}{bc\left(b+c\right)}+\frac{1}{ac\left(a+c\right)}\ge\frac{87}{2}\)

3. \(\left\{{}\begin{matrix}a,b,c>0\\ab+bc+ca=2abc\end{matrix}\right.\). Cmr: \(\frac{1}{a\left(2a-1\right)^2}+\frac{1}{b\left(2b-1\right)^2}+\frac{1}{c\left(2c-1\right)^2}\ge\frac{1}{2}\)

4. \(\left\{{}\begin{matrix}x,y,z>0\\x+y+z=2015\end{matrix}\right.\). Tìm min \(A=\frac{x^4+y^4}{x^3+y^3}+\frac{y^4+z^4}{y^3+z^3}+\frac{z^4+x^4}{z^2+x^2}\)

Mn giúp mk với ạ! Thanks nhiều

1,CMR nếu a,b,c x,y,z thỏa mãn điều kiện :

\(\frac{bz+cy}{x\left(-ax+by+cz\right)}=\frac{cx+az}{y\left(ax-by+cz\right)}=\frac{ay+bx}{z\left(ax+by-cz\right)}\)

thì \(\frac{x}{a\left(b^2+c^2-a^2\right)}=\frac{y}{b\left(a^2+c^2-b^2\right)}=\frac{z}{c\left(a^2+b^2-c^2\right)}\)

( giả thiết các tỉ số đều có nghĩa )

2,CMR nếu \(\frac{a+bx}{b+cy}=\frac{b+cx}{c+ay}=\frac{c+ax}{a+by}\)

thì \(a^3+b^3+c^3-3abc=0\)

3,CMR nếu \(x+\frac{1}{y}=y+\frac{1}{z}=z+\frac{1}{x}\)

thì x=y=z hoặc x²y²z²=1

Bài 1: Chứng minh rằng với mọi a, b, c, d>0, ta có:

\(\sqrt{ab}+\sqrt{cd}\le\sqrt{\left(a+d\right)\left(b+c\right)}\)

Bài 2: Cho x,y,z>0 và x²+y²+z²=3. CMR: \(\frac{1}{1+xy}+\frac{1}{1+yz}+\frac{1}{1+zx}\ge\frac{3}{2}\)

Bài 3: Cho a,b,c>1 và \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=2\).CMR: \(\sqrt{a-1}+\sqrt{b-1}+\sqrt{c-1}\le\sqrt{a+b+c}\)

1)Chứng minh rằng nếu n là số tự nhiên sao cho n+1 và 2n+1 đều là các số chính phương thì n là bội của 24

2) CMR nếu:

\(\frac{bz+cy}{x\left(-ax+by+cz\right)}=\frac{cx+az}{y\left(ax-by+cz\right)}=\frac{ay+bx}{z\left(ax+by-cz\right)}\left(1\right)\)

thì \(\frac{x}{a\left(b^2+c^2-a^2\right)}=\frac{y}{b\left(c^2+a^2-b^2\right)}=\frac{z}{c\left(a^2+b^2-c^2\right)}\)

3) Cho độ dài ba cạnh a,b,c của một tam giác. CMR:

\(\left(a+b+c\right)\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)+3\frac{\left(a-b\right)\left(b-c\right)\left(c-a\right)}{abc}\ge9\)

1.

a/ cho 6 số dương a,b,c,x,y,z thỏa mãn : ax+by+cz=xyz. cmr: \(x+y+z>\sqrt{a+b}+\sqrt{b+c}+\sqrt{c+a}\)

b/ cm: \(\sqrt{\frac{a}{b+c}}+\sqrt{\frac{b}{a+c}}+\sqrt{\frac{c}{b+c}}>2\) với a,b,c >0

2.

a/ cho \(\left(x+\sqrt{x^2+2013}\right).\left(y+\sqrt{y^2+2013}\right)=2013\)

b/ cho a,b là các số tự nhiên .cmr : \(5a^2+15ab-b^2⋮49\Leftrightarrow3a+b⋮7\)